Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.3 - Solving Quadratic Equations Using Square Roots - Exercises - Page 501: 16

Answer

$x=10$ and $x=-10$

Work Step by Step

The given equation is $\Rightarrow 4x^2-371=29$ Add $371$ to each side. $\Rightarrow 4x^2-371+371=29+371$ Simplify. $\Rightarrow 4x^2=400$ Divide each side by $4$. $\Rightarrow \frac{4x^2}{4}=\frac{400}{4}$ Simplify. $\Rightarrow x^2=100$ Take the square root of each side. $\Rightarrow x=\pm\sqrt {100}$ Simplify. $\Rightarrow x=\pm10$ Hence, the solutions are $x=10$ and $x=-10$.
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