Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.3 - Solving Quadratic Equations Using Square Roots - Exercises - Page 501: 18

Answer

$x=\frac{7}{3}$ and $x=-\frac{7}{3}$

Work Step by Step

The given equation is $\Rightarrow 9x^2-35=14$ Add $35$ to each side. $\Rightarrow 9x^2-35+35=14+35$ Simplify. $\Rightarrow 9x^2=49$ Divide each side by $9$. $\Rightarrow \frac{9x^2}{9}=\frac{49}{9}$ Simplify. $\Rightarrow x^2=\frac{49}{9}$ Take the square root of each side. $\Rightarrow x=\pm\sqrt {\frac{49}{9}}$ Simplify. $\Rightarrow x=\pm\frac{7}{3}$ Hence, the solutions are $x=\frac{7}{3}$ and $x=-\frac{7}{3}$.
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