Answer
The equation has no real solutions.
Work Step by Step
$3x^{2}+12=0\implies 3x^{2}=-12$ or $x^{2}=-\frac{12}{3}=-4$
Since the square of a real number cannot be negative, the equation has no real solutions.
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 9 - Solving Quadratic Equations - 9.3 - Solving Quadratic Equations Using Square Roots - Exercises - Page 501: 11
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