Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 485: 31

Answer

$-4x\sqrt[3]{x^2}$.

Work Step by Step

The given expression is $=\sqrt[3]{-64x^5}$ Factor as cube terms. $=\sqrt[3]{-64x^3\cdot x^2}$ Use product property of cube roots. $=\sqrt[3]{-64}\cdot \sqrt[3]{x^3}\cdot \sqrt[3]{x^2}$ Use $-64=(-4)^3$. $=\sqrt[3]{(-4)^3}\cdot \sqrt[3]{x^3}\cdot \sqrt[3]{x^2}$ Simplify. $=-4x\sqrt[3]{x^2}$.
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