Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 485: 37

Answer

The first step $\sqrt{4\cdot 18}$ is wrong and the correct answer is $6 \sqrt{2}$

Work Step by Step

The given expression is $=\sqrt{72}$ Factor as square terms. $=\sqrt{4\cdot 9 \cdot 2}$ Use product property of square roots. $=\sqrt{4}\cdot \sqrt{9} \cdot \sqrt{2}$ Use $4=2^2$ and $9=3^2$. $=\sqrt{2^2}\cdot \sqrt{3^2} \cdot \sqrt{2}$ Simplify. $=2\cdot 3 \cdot \sqrt{2}$ Multiply. $=6 \sqrt{2}$ Hence, the first step $\sqrt{4\cdot 18}$ is wrong and the correct answer is $6 \sqrt{2}$
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