Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 485: 20

Answer

$4n^2\sqrt{3n}$.

Work Step by Step

The given expression is $=\sqrt{48n^5}$ Factor as square terms. $=\sqrt{16n^4\cdot 3n}$ Use product property of square roots. $=\sqrt{16}\cdot \sqrt{n^4}\cdot \sqrt{3n}$ Use $16=4^2$. $=\sqrt{4^2}\cdot \sqrt{n^4}\cdot \sqrt{3n}$ Simplify. $=4n^2\sqrt{3n}$.
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