Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.4 - Solving Absolute Value Equations - Exercises - Page 33: 44

Answer

The solution is $x=\frac{3}{2}$.

Work Step by Step

The given equation is $\Rightarrow |3x-4|=|3x-5|$ Write the two related linear equations. $3x-4=3x-5$ ...... (1) $3x-4=-(3x-5)$ ...... (2) Solve equation (1). $\Rightarrow 3x-4=3x-5$ Add $5-3x$ to each side. $\Rightarrow 3x-4+5-3x=3x-5+5-3x$ Simplify. $\Rightarrow 1=0$ False statement. No solution. Solve equation (2). $\Rightarrow 3x-4=-(3x-5)$ Clear the parentheses. $\Rightarrow 3x-4=-3x+5$ Add $3x+4$ to each side. $\Rightarrow 3x-4+3x+4=-3x+5+3x+4$ Simplify. $\Rightarrow 6x=9$ Divide each side by $6$. $\Rightarrow \frac{6x}{6}=\frac{9}{6}$ Simplify. $\Rightarrow x=\frac{3}{2}$ Check : $x=\frac{3}{2}$ $\Rightarrow |3x-4|=|3x-5|$ $\Rightarrow |3(\frac{3}{2})-4|=|3(\frac{3}{2})-5|$ $\Rightarrow |\frac{9}{2}-4|=|\frac{9}{2}-5|$ $\Rightarrow |\frac{9-8}{2}|=|\frac{9-10}{2}|$ $\Rightarrow |\frac{1}{2}|=|\frac{-1}{2}|$ $\Rightarrow \frac{1}{2}=\frac{1}{2}$ True. Hence, the solution is $x=\frac{3}{2}$.
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