Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.4 - Solving Absolute Value Equations - Exercises - Page 33: 41

Answer

The solution is $h=\frac{1}{4}$.

Work Step by Step

The given equation is $\Rightarrow |3h+1|=7h$ Write the two related linear equations. $3h+1=7h$ ...... (1) $3h+1=-7h$ ...... (2) Solve equation (1). $\Rightarrow 3h+1=7h$ Subtract $3h$ from each side. $\Rightarrow 3h+1-3h=7h-3h$ Simplify. $\Rightarrow 1=4h$ Divide each side by $4$. $\Rightarrow \frac{1}{4}=\frac{4h}{4}$ Simplify. $\Rightarrow \frac{1}{4}=h$ Check : $h=\frac{1}{4}$ $\Rightarrow |3h+1|=7h$ $\Rightarrow |3(\frac{1}{4})+1|=7(\frac{1}{4})$ $\Rightarrow |\frac{3}{4}+1|=\frac{7}{4}$ $\Rightarrow |\frac{3+4}{4}|=\frac{7}{4}$ $\Rightarrow |\frac{7}{4}|=\frac{7}{4}$ $\Rightarrow \frac{7}{4}=\frac{7}{4}$ True. Solve equation (2). $\Rightarrow 3h+1=-7h$ Subtract $3h$ from each side. $\Rightarrow 3h+1-3h=-7h-3h$ Simplify. $\Rightarrow 1=-10h$ Divide each side by $-10$. $\Rightarrow -\frac{1}{10}=\frac{-10h}{-10}$ Simplify. $\Rightarrow -\frac{1}{10}=h$ Check : $h=-\frac{1}{10}$ $\Rightarrow |3h+1|=7h$ $\Rightarrow |3(-\frac{1}{10})+1|=7(-\frac{1}{10})$ $\Rightarrow |-\frac{3}{10}+1|=-\frac{7}{10}$ $\Rightarrow |\frac{-3+10}{10}|=-\frac{7}{10}$ $\Rightarrow |\frac{7}{10}|=-\frac{7}{10}$ $\Rightarrow \frac{7}{10}=-\frac{7}{10}$ False. Hence, the solution is $h=\frac{1}{4}$.
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