Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.4 - Solving Absolute Value Equations - Exercises - Page 33: 43

Answer

The solution is $f=-1$.

Work Step by Step

The given equation is $\Rightarrow |f-6|=|f+8|$ Write the two related linear equations. $f-6=f+8$ ...... (1) $f-6=-(f+8)$ ...... (2) Solve equation (1). $\Rightarrow f-6=f+8$ Add $6-f$ to each side. $\Rightarrow f-6+6-f=f+8+6-f$ Simplify. $\Rightarrow 0=14$ False statement. No solution. Solve equation (2). $\Rightarrow f-6=-(f+8)$ Clear the parentheses. $\Rightarrow f-6=-f-8$ Add $f+6$ to each side. $\Rightarrow f-6+f+6=-f-8+f+6$ Simplify. $\Rightarrow 2f=-2$ Divide each side by $2$. $\Rightarrow \frac{2f}{2}=-\frac{2}{2}$ Simplify. $\Rightarrow f=-1$ Check : $f=-1$ $\Rightarrow |f-6|=|f+8|$ $\Rightarrow |-1-6|=|-1+8|$ $\Rightarrow |-7|=|7|$ $\Rightarrow 7=7$ True. Hence, the solution is $f=-1$.
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