Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.4 - Solving Absolute Value Equations - Exercises - Page 33: 40

Answer

The solutions are $w=-2$ and $w=-\frac{1}{5}$.

Work Step by Step

The given equation is $\Rightarrow 2|4w-1|=3|4w+2|$ Write the two related linear equations. $2(4w-1)=3(4w+2)$ ...... (1) $2(4w-1)=3[-(4w+2)]$ ...... (2) Solve equation (1). $\Rightarrow 2(4w-1)=3(4w+2)$ Use distributive property. $\Rightarrow 8w-2=12w+6$ Add $-8w-6$ to each side. $\Rightarrow 8w-2-8w-6=12w+6-8w-6$ Simplify. $\Rightarrow -8=4w$ Divide each side by $4$. $\Rightarrow \frac{-8}{4}=\frac{4w}{4}$ Simplify. $\Rightarrow -2=w$ Check : $w=-2$ $\Rightarrow 2|4w-1|=3|4w+2|$ $\Rightarrow 2|4(-2)-1|=3|4(-2)+2|$ $\Rightarrow 2|-8-1|=3|-8+2|$ $\Rightarrow 2|-9|=3|-6|$ $\Rightarrow 2(9)=3(6)$ $\Rightarrow 18=18$ True. Solve equation (2). $\Rightarrow 2(4w-1)=3[-(4w+2)]$ Use distributive property. $\Rightarrow 8w-2=-12w-6$ Add $12w+2$ to each side. $\Rightarrow 8w-2+12w+2=-12w-6+12w+2$ Simplify. $\Rightarrow 20w=-4$ Divide each side by $20$. $\Rightarrow \frac{20w}{20}=\frac{-4}{20}$ Simplify. $\Rightarrow w=-\frac{1}{5}$ Check : $w=-\frac{1}{5}$ $\Rightarrow 2|4w-1|=3|4w+2|$ $\Rightarrow 2|4(-\frac{1}{5})-1|=3|4(-\frac{1}{5})+2|$ $\Rightarrow 2|-\frac{4}{5}-1|=3|-\frac{4}{5}+2|$ $\Rightarrow 2|\frac{-4-5}{5}|=3|\frac{-4+10}{5}|$ $\Rightarrow 2|\frac{-9}{5}|=3|\frac{6}{5}|$ $\Rightarrow 2(\frac{9}{5})=3(\frac{6}{5})$ $\Rightarrow \frac{18}{5}=\frac{18}{5}$ True. Hence, the solutions are $w=-2$ and $w=-\frac{1}{5}$.
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