Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.4 - Solving Absolute Value Equations - Exercises - Page 33: 37

Answer

The solutions are $b=3$ and $b=5$.

Work Step by Step

The given equation is $\Rightarrow |2b-9|=|b-6|$ Write the two related linear equations. $2b-9=b-6$ ...... (1) $2b-9=-(b-6)$ ...... (2) Solve equation (1). $\Rightarrow 2b-9=b-6$ Add $9-b$ to each side. $\Rightarrow 2b-9+9-b=b-6+9-b$ Simplify. $\Rightarrow b=3$ Check : $b=3$ $\Rightarrow |2b-9|=|b-6|$ $\Rightarrow |2(3)-9|=|3-6|$ $\Rightarrow |6-9|=|-3|$ $\Rightarrow |-3|=|-3|$ True. Solve equation (2). $\Rightarrow 2b-9=-(b-6)$ Simplify. $\Rightarrow 2b-9=-b+6$ Add $9+b$ to each side. $\Rightarrow 2b-9+9+b=-b+6+9+b$ Simplify. $\Rightarrow 3b=15$ Divide each side by $3$. $\Rightarrow \frac{3b}{3}=\frac{15}{3}$ Simplify. $\Rightarrow b=5$ Check : $b=5$ $\Rightarrow |2b-9|=|b-6|$ $\Rightarrow |2(5)-9|=|5-6|$ $\Rightarrow |10-9|=|-1|$ $\Rightarrow |1|=|-1|$ $\Rightarrow 1=1$ True. Hence, the solutions are $b=3$ and $b=5$.
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