Answer
$tan^2x(csc^2x-1)=1$
Work Step by Step
$1+cot^2x=csc^2x$
$cot^2x=csc^2x-1$
$tan~x=\frac{1}{cot~x}$
$tan~x~cot~x=1$
$tan^2x(csc^2x-1)=tan^2x~cot^2x=(tan~x~cot~x)^2=1^2=1$
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