Answer
The identity is verified.
$cos~x~(1+tan^2x)=sec~x$
Work Step by Step
$1+tan^2x=sec^2x~~$ (Pythagorean identity):
$cos~x=\frac{1}{sec~x}$
$cos~x~(1+tan^2x)=cos~x~sec^2x=\frac{1}{sec~x}~sec^2x=sec~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 19
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