Answer
$\frac{tan~θ}{1-cos^2θ}=\frac{1}{sin~θ~cos~θ}=csc~θ~sec~θ$
Work Step by Step
$sin^2θ+cos^2θ=1$
$sin^2θ=1-cos^2θ$
$tan~θ=\frac{sin~θ}{cos~θ}$
$\frac{tan~θ}{1-cos^2θ}=\frac{\frac{sin~θ}{cos~θ}}{sin^2θ}=\frac{1}{sin~θ~cos~θ}=csc~θ~sec~θ$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 8
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