Answer
$x=0$
$x=\frac{\pi}{2}$
$x=\pi$
$x=\frac{3\pi}{2}$
Work Step by Step
$sin^3x=sin~x$
$sin^3x-sin~x=0$
$sin~x(sin^2x-1)=0$
$sin~x=0$
$x=0$ or $x=\pi$
$sin^2x-1=0$
$sin^2x=1$
$sin~x=±1$
$x=\frac{\pi}{2}$ or $x=\frac{3\pi}{2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - Review Exercises - Page 552: 33
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