Answer
$\frac{tan~68°-tan~115°}{1+tan~68°~tan~115°}=-tan~47°$
Work Step by Step
$tan(u-v)=\frac{tan~u-tan~v}{1+tan~u~tan~v}$
$\frac{tan~68°-tan~115°}{1+tan~68°~tan~115°}=tan (68°-115°)=tan(-47°)=-tan~47°$
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