Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 339: 82

Answer

$(12(-1+\sqrt {5}),0)$

Work Step by Step

$\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$ $\implies \dfrac{x^2}{a^2}-\dfrac{y^2}{c^2-a^2}=1$ $\implies \dfrac{(24)^2}{a^2}-\dfrac{(24)^2}{576-a^2}=1$ $\implies a^4-1728a^2+331776=0$ $\implies (a^2-24a-576) (a^2+24a-576)=0$ or, $a=12(-1+\sqrt {5})$ The coordinates of the vertex are: $(12(-1+\sqrt {5}),0)$
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