Answer
Vertices: $(0,±\frac{1}{2})$
Asymptotes: $y=±\frac{1}{2}x~~$ (Black Lines)
Work Step by Step
Standard form when transverse axis is vertical:
$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$
$4y^2-x^2=225$
$\frac{y^2}{\frac{1}{4}}-\frac{x^2}{1}=1$
$a^2=\frac{1}{4}$
$a=\frac{1}{2}$
$b^2=1$
$b=1$
Vertices when transverse axis is vertical:
$(0,±a)=(0,±\frac{1}{2})$
Asymptotes when transverse axis is vertical:
$y=±\frac{a}{b}x$
$y=±\frac{\frac{1}{2}}{1}x=±\frac{1}{2}x$
