Answer
$x^2-\frac{y^2}{9}=1$
Work Step by Step
Transverse axis is horizontal.
$(±a,0)=(±1,0)$
$a=1$
The equation of the asymptotes when transverse axis is horizontal:
$y=±\frac{b}{a}x$
The equation of the asymptotes:
$y=±3x$
So:
$\frac{b}{a}=3$
$\frac{b}{1}=3$
$b=3$
Standard form when transverse axis is horizontal:
$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
$\frac{x^2}{1^2}-\frac{y^2}{3^2}=1$
$\frac{x^2}{1}-\frac{y^2}{9}=1$
$x^2-\frac{y^2}{9}=1$
