Answer
Vertices: $(±5,0)$
Asymptotes:
$y=±x~~$ (Black lines)
Work Step by Step
Standard form when transverse axis is horizontal:
$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
$a^2=25$
$a=5$
$b^2=25$
$b=5$
Vertices when transverse axis is horizontal: $(±a,0)=(±5,0)$
Asymptotes when transverse axis is horizontal:
$y=±\frac{b}{a}x=±\frac{5}{5}x$
$y=±x$
