Answer
Vertices: $(0,±3)$
Asymptotes: $y=±\frac{3}{5}x$
Work Step by Step
Standard form when transverse axis is vertical:
$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$
$25y^2-9x^2=225$
$\frac{y^2}{9}-\frac{x^2}{25}=1$
$a^2=9$
$a=3$
$b^2=25$
$b=5$
Vertices when transverse axis is vertical:
$(0,±a)=(0,±3)$
Asymptotes when transverse axis is vertical:
$y=±\frac{a}{b}x$
$y=±\frac{3}{5}x$
