Answer
Vertices: $(0,±1)$
Asymptotes: $y=±\frac{1}{2}x$
Work Step by Step
Standard form when transverse axis is vertical:
$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$
$2y^2-\frac{x^2}{2}=2$
$\frac{y^2}{1}-\frac{x^2}{4}=1$
$a^2=1$
$a=1$
$b^2=4$
$b=2$
Vertices when transverse axis is vertical:
$(0,±a)=(0,±1)$
Asymptotes when transverse axis is vertical:
$y=±\frac{a}{b}x$
$y=±\frac{1}{2}x$
