Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 28

Answer

$$y=\sqrt[4]{2}\sqrt[4]{x},\:y=-\sqrt[4]{2}\sqrt[4]{x}$$

Work Step by Step

Switching the elements of the domain and the range (in other words, the dependent and independent variables), we find that the inverse is: $$x=\frac{1}{2}y^4 \\ y=\sqrt[4]{2}\sqrt[4]{x},\:y=-\sqrt[4]{2}\sqrt[4]{x}$$
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