Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 20

Answer

$$\frac{2x+9}{3x-1}$$

Work Step by Step

Plugging in $f(x)=2x+9$ and $g(x)=3x-1$, we find: $$f=2x+9,\:g=3x-1,\:\frac{f\left(x\right)}{g\left(x\right)} \\ \frac{2x+9}{3x-1}$$
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