Answer
$$4x^{4/3}y^{2/3}$$
Work Step by Step
Using the rules of radicals to simplify, we find:
$$\sqrt[3]{64}\sqrt[3]{x^4y^2} \\ 4\sqrt[3]{x^4y^2} \\ 4x^{4/3}y^{2/3}$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 13
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