Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 12

Answer

$$\frac{2}{3^{1/3}}$$

Work Step by Step

Using the rules of radicals to simplify, we find: $$\frac{2\sqrt[3]{3}}{\sqrt[3]{9}} \\ \frac{2\cdot \:3^{\frac{2}{3}}}{3} \\ \frac{2\cdot \:3^{\frac{2}{3}}}{3} \\ \frac{2}{3^{1/3}}$$
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