Answer
$$2^{\frac{7}{5}}$$
Work Step by Step
Using the rules of radicals to simplify, we find:
$$\sqrt[5]{2^4}\sqrt[5]{8} \\ 2^{\frac{4}{5}}\sqrt[5]{2^3}\\ 2^{\frac{4}{5}}\cdot \:2^{\frac{3}{5}}\\ 2^{\frac{7}{5}}$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 10
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