Answer
See below
Work Step by Step
Using the rules of radicals to simplify, we find:
$$\sqrt[4]{2x^6y^8z}\\=\sqrt[4]{2}\sqrt[4] {x^4}\sqrt[4] {x^2}\sqrt[4] y^4 \sqrt[4] y^4\sqrt[4] z\\ =\sqrt[4]2 .x.\sqrt[y] x^2.y.y.\sqrt[4] z \\ = xy^2\sqrt[4] 2x^2z$$