Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 14

Answer

See below

Work Step by Step

Using the rules of radicals to simplify, we find: $$\sqrt[4]{2x^6y^8z}\\=\sqrt[4]{2}\sqrt[4] {x^4}\sqrt[4] {x^2}\sqrt[4] y^4 \sqrt[4] y^4\sqrt[4] z\\ =\sqrt[4]2 .x.\sqrt[y] x^2.y.y.\sqrt[4] z \\ = xy^2\sqrt[4] 2x^2z$$
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