Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Mixed Review - Page 368: 56

$x=-1 \pm 3i$

Given: $x^2+2x+10=0$ The equation is in quadratic form $ax^2+bx+c=0$ with $a=1, b=2, c=10$. Hence, the solution of the equation is: $x=\frac{-b\pm\sqrt b^2-4ac}{2a}$ $x=\frac{-2 \pm \sqrt 2^2-4.1.10}{2.1}$ $x=\frac{-2 \pm \sqrt -36}{2}$ $x=\frac{-2 \pm i\sqrt 36}{2}$ $x=\frac{-2 \pm 6i}{2}$ $x=-1 \pm 3i$