Answer
$\frac{-7 \pm \sqrt 41}{2}$
Work Step by Step
To find the solution for the equation, apply $x=\frac{-x \pm \sqrt b^2-4ac}{2a}$
Substitute: $a=1\\b=7\\c=2$:
$x=\frac{-7 \pm \sqrt 7^2-4.1.2}{2.1}=\frac{-7 \pm \sqrt 41}{2}$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Mixed Review - Page 368: 53
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