Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Mixed Review - Page 368: 48

The solution is $(-2,4)$

Given: $3x+2y \geq1$ Substitute $(-2,4)$: $3(-2)+2(4) \geq1$ $-6+8 \geq 1$ $2 \geq 1 \rightarrow$ True Substitute $(1,-3)$: $3.1+2(-3) \geq1$ $3-6 \geq 1$ $-3 \geq 1\rightarrow $ False Hence, the solution is $(-2,4)$.