Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Mixed Review - Page 368: 54

$x=\frac{-15 \pm \sqrt 65}{8}$

Givne: $4x^2+15x+10=0$ The equation is in the form $ax^2+bx+c=0$ with $a=4, b=15, c=10$ Hence, the solution of the equation is: $x=\frac{-b\pm\sqrt b^2-4ac}{2a}$ $x=\frac{-15 \pm \sqrt 15^2-4.4.10}{2.4}$ $x=\frac{-15 \pm \sqrt 65}{8}$