Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Mixed Review - Page 368: 50

The solution is $(-1,4)$.

Given: $6x+5y\leq15$ Substitute $(-5,10)$: $6(-5)+5.10\leq15$ $-30+50\leq15$ $20\leq15→False$ Substitute $(-1,4)$: $6(-1)+5.4\leq15$ $-6+20 \leq15$ $14\leq15→ True$ Hence, the solution is $(-1,4)$.