Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.3 Exercises - Skill Practice - Page 870: 5

Answer

$\sin \theta=\dfrac{-24}{25}$ $\cos \theta=\dfrac{-7}{25}$ $\tan \theta=\dfrac{24}{7}$ $\csc \theta=\dfrac{-25}{24}$ $\sec \theta=\dfrac{-25}{7}$ $\cot \theta=\dfrac{7}{24}$

Work Step by Step

$r=\sqrt {(-7)^2+(-24)^2}=25$ The Trigonometric Identities can be defined as: $\sin \theta=\dfrac{Opposite}{Hypotenuse}=\dfrac{-24}{25}$ $\cos \theta=\dfrac{Adjacent}{Hypotenuse}=\dfrac{-7}{25}$ $\tan \theta=\dfrac{Opposite}{Adjacent}=\dfrac{24}{7}$ $\csc \theta=\dfrac{Hypotenuse}{Opposite}=\dfrac{-25}{24}$ $\sec \theta=\dfrac{Hypotenuse}{Adjacent}=\dfrac{-25}{7}$ $\cot \theta=\dfrac{Adjacent}{Opposite}=\dfrac{7}{24}$
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