Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.3 Evaluate Trigonometric Functions of Any Angle - 13.3 Exercises - Skill Practice - Page 870: 3

Answer

$\sin \theta=\dfrac{15}{17}$ $\cos \theta=\dfrac{8}{17}$ $\tan \theta=\dfrac{15}{8}$ $\csc \theta=\dfrac{17}{15}$ $\sec \theta=\dfrac{17}{8}$ $\cot \theta=\dfrac{8}{15}$

Work Step by Step

The Trigonometric Identities can be defined as: $\sin \theta=\dfrac{Opposite}{Hypotenuse}=\dfrac{15}{17}$ $\cos \theta=\dfrac{Adjacent}{Hypotenuse}=\dfrac{8}{17}$ $\tan \theta=\dfrac{Opposite}{Adjacent}=\dfrac{15}{8}$ $\csc \theta=\dfrac{Hypotenuse}{Opposite}=\dfrac{17}{15}$ $\sec \theta=\dfrac{Hypotenuse}{Adjacent}=\dfrac{17}{8}$ $\cot \theta=\dfrac{Adjacent}{Opposite}=\dfrac{8}{15}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.