Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 510: 47

x(8x+5)(7x+1)

Given the polynomial x($56x^{2}$ + 43x + 5) *** We break of the middle term into two factors that add to give +43 and multiply to give +280. The two numbers are +35 and +8. x($56x^{2}$ + 8x + 35x + 5) We take the GCD of the first two and the GCD of the last two terms. x(8x(7x+1)+5(7x+1)) We take (7x+1) and factor it out which gives us. x(8x+5)(7x+1)