Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 510: 45

(7g-6)(9g-5)

Given the polynomial $63g^{2}$ - 89g + 30 *** We break of the middle term into two factors that add to give -89 and multiply to give +1890. The two numbers are -54 and -35. $63g^{2}$ - 35g - 54g + 30 We take the GCD of the first two and the GCD of the last two terms. 7g(9g-5) -6(9g-5) We take (9g-5) and factor it out which gives us. (7g-6)(9g-5)