Answer
2(6p-1)(3p+10)
Work Step by Step
Given the polynomial
$36p^{2}$ + 114p - 20
We see that the three terms have a common factor of 2 so we factor out a 2.
2($18p^{2}$ + 57p - 10)
*** We break of the middle term into two factors that add to give +57 and multiply to give -180. The two numbers are +60 and -3.
2($18p^{2}$ + 60p - 3p - 10)
We take the GCD of the first two and the GCD of the last two terms.
2(6p(3p+10)-1(3p+10))
We take (3p+10) and factor it out which gives us.
2(6p-1)(3p+10)
