Answer
28(h+2)(h-1)
Work Step by Step
Given the polynomial
$28h^{2}$ + 28h - 56
We see that the three terms have a common factor of 28 so we factor out 28.
28($h^{2}$ + h - 2)
*** We break of the middle term into two factors that add to give +1 and multiply to give -2. The two numbers are +2 and -1.
28($h^{2}$ + 2h - h - 2)
We take the GCD of the first two and the GCD of the last two terms.
28(h(h+2)-1(h+2))
We take (h+2) and factor it out which gives us.
28(h+2)(h-1)
