Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 510: 40

(2z-7)(7z-2)

Given the polynomial $14z^{2}$ - 53z + 14 *** We break of the middle term into two factors that add to give -53 and multiply to give +196. The two numbers are -49 and -4. $14z^{2}$ - 49z - 4z + 14 We take the GCD of the first two and the GCD of the last two terms. 7z(2z-7) -2(2z-7) We take (2z-7) and factor it out which gives us. (2z-7)(7z-2)