Answer
3(2k+1)(11k+4)
Work Step by Step
Given the polynomial
$66k^{2}$ + 57k + 12
We see that the three terms have a common factor of 3 so we factor out a 3.
3($22k^{2}$ + 19k + 4)
*** We break of the middle term into two factors that add to give +19 and multiply to give 88. The two numbers are +8 and +11.
3($22k^{2}$ + 8k + 11k + 4)
We take the GCD of the first two and the GCD of the last two terms.
3(2k(11k+4)+1(11k+4))
We take (11k+4) and factor it out which gives us.
3(2k+1)(11k+4)
