Answer
$\frac{2b^{5}}{3a}$
Work Step by Step
=$\frac{(6a^{3})(8b^{4})}{(2a^{4}(36b^{-1})}$
=$\frac{48a^{3}b^{4}}{72a^{4}b^{-1}}$
=$\frac{48a^{3-3}b^{4+1}}{72a^{4-3}b^{-1+1}}$
=$\frac{48b^{5}}{72a}$
=$\frac{2b^{5}}{3a}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 445: 78
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