Answer
$\frac{x^{6}}{9y^{8}}$
Work Step by Step
$(\frac{3xy^{5}}{x^{4}y})^{-2}$
$(\frac{3x^{1-1}y^{5-1}}{x^{4-1}y^{1-1}})^{-2}$
$(\frac{3y^{4}}{x^{3}})^{-2}$
$(\frac{x^{3}}{3y^{4}})^{2}$
$\frac{x^{6}}{9y^{8}}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 445: 71
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