Answer
$\frac{y^{10}}{2x^{5}}$
Work Step by Step
Given : $\frac{4}{8}\times$$\frac{x^{-2}}{x^{3}}\times$$\frac{y^{4}}{y^{-6}}$
This becomes : $\frac{1}{2}\times$$x^{-2-3}\times$$y^{4-(-6)}=$$\frac{1}{2}\times$$x^{-5}\times$$y^{10}$
(since $\frac{a^{m}}{a^{n}}=$ $a^{m-n}$)
Final result : $\frac{y^{10}}{2x^{5}}$
(since $a^{-n}=$ $\frac{1}{a^{n}}$)
