Answer
$\frac{2}{27}$
Work Step by Step
=$\frac{(\frac{1}{4})^{-2}}{(\frac{1}{6})^{-3}}$
=$\frac{\frac{1}{4^{-2}}}{\frac{1}{6^{-3}}}$
=$\frac{4^{2}}{6^{3}}$
=$\frac{16}{216}$
=$\frac{2}{27}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 445: 73
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