Answer
$\frac{1}{16m^{8}}$
Work Step by Step
$(\frac{2m^{4}}{m^{2}})^{-4}$
$(2m^{4-2})^{-4}$
$(2m^{2})^{-4}$
$(\frac{1}{2m^{2}})^{4}$
$\frac{1}{16m^{8}}$
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