Answer
$\frac{1}{a^{9}}$
Work Step by Step
$(\frac{a^{4}a}{a^{2}})^{-3}$
$(\frac{a^{5}}{a^{2}})^{-3}$
$(a^{3})^{-3}$
$\frac{1}{(a^{3})^{3}}$
$\frac{1}{a^{9}}$
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