Answer
no solution
Work Step by Step
$\sqrt {7p+5} = \sqrt{p-3}$
$(\sqrt {7p+5})^2 =(\sqrt{p-3})^2$
$7p+5 = p-3$
$7p+5-p+3 = p-3-p+3$
$6p+8 = 0$
$(6p+8)/2 = 0/2$
$3p+4 = 0$
$3p+4-4 = 0-4$
$3p= -4$
$3p/3 = -4/3$
$p = -4/3$
$\sqrt {7p+5} = \sqrt{p-3}$
$\sqrt {7*-4/3+5} = \sqrt{-4/3-3}$
$\sqrt {-28/3+5} = \sqrt{-4/3+-3}$
$\sqrt {-43/3} \ne \sqrt {-13/3}$ (no solution)