Answer
no solution
Work Step by Step
$-6-\sqrt {3y} = -3$
$-6-\sqrt {3y}+\sqrt {3y} +3 = -3+\sqrt {3y} +3$
$-3 = \sqrt {3y}$
$(-3)^2 = (\sqrt {3y})^2$
$9 = 3y$
$9/3 = 3y/3$
$y=3$
$-6-\sqrt {3y} = -3$
$-6-\sqrt {3*3} = -3$
$-6-\sqrt {9} = -3$
$-6- 3 = -3$
$-9 \ne -3$ (no solution)