Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 624: 44

Answer

no solution

Work Step by Step

$-6-\sqrt {3y} = -3$ $-6-\sqrt {3y}+\sqrt {3y} +3 = -3+\sqrt {3y} +3$ $-3 = \sqrt {3y}$ $(-3)^2 = (\sqrt {3y})^2$ $9 = 3y$ $9/3 = 3y/3$ $y=3$ $-6-\sqrt {3y} = -3$ $-6-\sqrt {3*3} = -3$ $-6-\sqrt {9} = -3$ $-6- 3 = -3$ $-9 \ne -3$ (no solution)
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