Answer
$y=2$
Work Step by Step
$Given,$
$\sqrt (2y) - \sqrt (y+2)=0$
$\sqrt (2y)-\sqrt (y+2) + \sqrt (y+2) = \sqrt (y+2)$
$\sqrt (2y)=\sqrt (y+2)$
Squaring,
$2y=y+2$
$2y-y=2$
$y=2$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 624: 41
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